(2v+4)(2v-4)=4v^2-8

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Solution for (2v+4)(2v-4)=4v^2-8 equation: 


Simplifying
(2v + 4)(2v + -4) = 4v2 + -8

Reorder the terms:
(4 + 2v)(2v + -4) = 4v2 + -8

Reorder the terms:
(4 + 2v)(-4 + 2v) = 4v2 + -8

Multiply (4 + 2v) * (-4 + 2v)
(4(-4 + 2v) + 2v * (-4 + 2v)) = 4v2 + -8
((-4 * 4 + 2v * 4) + 2v * (-4 + 2v)) = 4v2 + -8
((-16 + 8v) + 2v * (-4 + 2v)) = 4v2 + -8
(-16 + 8v + (-4 * 2v + 2v * 2v)) = 4v2 + -8
(-16 + 8v + (-8v + 4v2)) = 4v2 + -8

Combine like terms: 8v + -8v = 0
(-16 + 0 + 4v2) = 4v2 + -8
(-16 + 4v2) = 4v2 + -8

Reorder the terms:
-16 + 4v2 = -8 + 4v2

Add '-4v2' to each side of the equation.
-16 + 4v2 + -4v2 = -8 + 4v2 + -4v2

Combine like terms: 4v2 + -4v2 = 0
-16 + 0 = -8 + 4v2 + -4v2
-16 = -8 + 4v2 + -4v2

Combine like terms: 4v2 + -4v2 = 0
-16 = -8 + 0
-16 = -8

Solving
-16 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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